1) FeCl3 +SO2 →
2)Fe2O3 +NaOH +Cl2 →
3)CuSO4.5H2O +KCN(excess)→
will add more later....
***not my doubts....just some exception reactions ***
11)FeCl3 acts as a oxidising agent and oxidises SO2 to H2SO4.
2FeCl3+SO2+2H2O→2FeCl2+H2 SO4+2HCl
2)I think it will give FeO. but not sure.
3)When d reaction of CuSO4 is done with KCN cupric cyanide is formed but it quickly decomposes to give cuprous cyanide and cyanogen. But in presence of excess KCN,Cuprous cyanide forms Potassium cuprocyanide.
1agree with ashish regardin 1,SO2 will reduce Fe3+ to Fe2+ and will get oxidised to H2SO4 in presence of water.
24well lubu made it for 1st one...
ans1=FeCl2+H2SO4+HCl
2,3 still waiitng to be answered....
132) Just giving it a shot.....
Cl2 will disproportionate in NaOH,
Cl2+NaOH ---> NaCl + NaOCl + H2O
But, since Fe3+ can't be oxidised phurther, it wud have no other option than to hydrolyse.
So, the final products can be- NaCl, NaOCl, Fe(OH)3.
3) Lubu ka answer sahi toh lagta hai.
1nahi saket, yarr excess KCN hone se Complex compund banega. K3\left[cu\left(CN \right)4 \right]called potassium Cuprocyanide will be formed.It will take 6moles of KCN.
1@Lubu : In ur #5 did u mean to give the products for Fecl 3 + H2O ???
Actually i din't mean to ask the products
I was giving the answer for 2nd one as Fecl 3 + H20
WHICH i think is wrong as confirmed by eureka123-R.I.P-
