24kk..thx
300g of water at 25C is aded to 100g ice at OC.Final temp of mix is ??
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2 Answers
29heat energy required for change of temperature of water from 25°C to 0°C = 25 * 300 *1 cal = 7500
heat energy liberated on conversion of ice to water at 0°C = 100 *80 =8000
Since 7500 < 8000..so not all ice will be converted into water...
And the temperature of the mixture will be 0°C....
Final situation
Amount of ice = 6.25 g
Amount of water = 393.75 g