1br2 is strong oxidising agent
so it shud not be surprising that NaBr is formed !
so y A ?
excess NH3 gives NCl3
13 Answers
1
106with hot and conc. NaOH, NaBr + NaBrO3 + H2O forms naa?
with excess of NH3, NH4Cl is formed if im not mistaken
so AD both wrong na?
1hmmm ....
but they did not say that NaBr and H2O are the only products formed
146.d
the stability of +2 OS increases down the group(inert pair effect)
1Q.46> stabilty of +2 ox. state increases down the grp..due to inert pair effect ans shud be (d).....not c as givn
47.>asish i chekd ncert .... both A and D are incorect...tho in the exam i wud hav markd only D as the ans
@asish : EDITTED
106@avinav: typo... pls correct that to "ans shud be (D) ..... not c as givn"
btw need help in 49
39Q49. Let the weight of the solution be 100 g.
So weight of sulfuric acid = 29 g.
Molarity of solution = WBMB x 1000Volume
3.6 = 29/98 x 1000/V
=> V = 3600 x 9829
=> V = 12165.5 mL = 12.165 L
Density = M/V = 29/12.165 g/L = 2.38 g/L??
Above is wrong.
Edited as per Manmay's request :
V = 29 x 100098 x 3.6
= 82.2 mL
Aa gaya
Density = M/V = 100/82.2 = 1.21
39Why else do you think I put the question marks after the answer?
And why else do you think asish has a doubt in the question?
Smarty pants you are, eh manmay? :P
Tell me where I'm wrong?
1but don't u thnk that's not in the given options pritish
moreover answers is asked in g mL-1
and u did calculation mistake [3]
39Oh? I used a calculator..
Abey yeh calculation mistake nahi hai...this is mistake in the expression! LOL
149.> 1 Ltr soln has 3.6 moles of acid= 3.6*98 g /L
now 100 gm contains 29gm of acid..
so 100/x ml of soln contains 29g of acid
again 1000ml contains=3.6*98
so x=3.6*98*10029*1000=1.22
to be honest i was unable to get the soln....got the hint from a book
13Asish, I'm wondering how come u posted this in the Mechanics section....hadbadi perhaps ;P
'coz I didn't open it seeing the section :D