331 kg
Block A is almost massless.and velocity is given to (mass=1kg) v=√8gH
Find acceleration of A at initial instant.
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13 Answers
11bhai yeh almost massless hai to why not erase it ???
and mass =1 ??
150 ms-2 ???[7]:P
pata nahin I'm ont convinced
the tension is found 50 N , then kya karna hai ???
how to find acceleration ???
11Acceleration of A will g + x
x will the acceleration of the mass 1 kg to reach the velocity v = √8gh in 2h distance
8*g*h = 2*x * 2h
2g = x
Acceleration = g + 2g
Accerelaration = 3g
33
s=1/2gt2 for very very small time 't'
y=vt
v=√8gH
x=1/2at2 a is acceleration of A
now (2H+s)2+y2=(2H+x)2
4H2+(1/2gt2)2+2gHt2+8gHt2=4H2+(1/2at2)2+2aHt2
(1/2gt2)2+2gHt2+8gHt2=(1/2at2)2+2aHt2
1/4g2t2+2gH+8gH=1/4g2t2+2aH
neglecting t2 terms
a=5g
33First I did the same. [3]
and got same answer
g+v2/2H=5g
but am not fully convinced about v2/2H.