AITS Qs.Fluid mechanics:

4m/s???????

no...

YAAR SHUD U NEGLECT GRAVITY OR NOT????

IN THE END UVE GIVEN VALUE OF g !!!!!!!!!!!!!!!!!!!

v=6m/s???

neglect gravity as in question,(i just copied the qs as it is where they hav given the value of g), ashish cud u xplain how u proceeded??

See pressure is a scalar quantity. So, pressure in the fluid just above the hole is ρgd + F/A where A= area of cylinder = Î d²/4

Now, applying Bernoulli,
Take h=0 at the hole position . hence ρgh=0
(P₀ + ρgd + F/A) + ρ(v₁)²/2 = P₀ + ρ(v₂)²/2

==> taking A₁ and A₂ and then neglecting A₂<<<A₁

we get ρ(v₂)²/2 = ρgd + F/A
As, gravity is neglected, ρgd=0

Put the necessary values and u get v₂ = 4m/s

VAHIN TOH ITS GIVEN NEGLECT GRAVITY SO THERES NO ρgd ................... without that we get 4

dont take ρgd as we hav neglect ravity...now check urs....

ans. kya hai????????? without grav itz surely root 14