first we shuld note that - 'decreases uniformly with the distance covered'
600 - 0 metre
400 - 15 metre
uniform decrease per metre = 200 / 15 = 40/3
force at a particular distance s is :
(600 - (40/3) * s) - 90 (resistive force) = 5000 * a
(600 - (40/3) * s) - 90 (resistive force) = 5000 * v dv/ds
ab integrate karo .. LHS limits : 0 to 15 and RHS unit 0 to v
u will get
[ 51s - (2/3)s2 ]015 = 250v2 | 0 v
solve ang get v = 1.568.... m/s
- ANKIT