3hey great vishal how it is zero can you explain me
The system is released from rest from the position show in thediagram If A and B have mass m and M respectively and all surfaces are smooth , then the normal reaction between A and B is assume that string and pulley are massles
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10 Answers
1well after release no motion will be there as
1. string is inextendable
2. on the basis of fig. i assumed that MA<MB
so no horizontal force hence normal reaction =0
1all surfaces are smooth...
draw FBD of m..
T upwrds, mg downwards, N1 leftwards..
forget vertical motion..(not reqd)
N1= ma (say) where a is horizontal acceleration..
but a=0
so N1=0.
3let us assume there is a frictionbetween the mass In this situation what will be the normal rxn
1mass B will only move if Ma>Mb
jst assumed dat Ma<Mb on basis of fig.(ie size of 2 masses)
if this is nt the case then it has to b gvn dat Ma>Mb
othrwise N=0
sky's method makes it more simpler