383
Soumyabrata Mondal
·Jan 20 '13 at 11:29
pressure=HÏg
slant surface area=πR√(R2+H2)
force=(Ï€R√(R2+H2))*HÏg
1133
Sourish Ghosh
·Jan 21 '13 at 6:27
Is it
Ï€R√(H2 + R2) 2[P0 + 23HÏg] ?
1161
Akash Anand
·Jan 21 '13 at 22:41
Think a bit different way.
337
Sayan Sinha
·Jan 22 '13 at 22:52
We can calculate the area of the slant height using Ï€R√(R2+H2). Then, find out the area of the triangle ABC. Area= RH/2. Then, we multiply the area with the area of slant height = RH/2 * Ï€R√(R2+H2). Let this value be k. D=M/V. So, M=DV. Density is Ï and volume is k. We multiply them and get mass=Ïk. To find out the force, we multiply it using g. So, final answer=
Ï RH Ï€R√(R2+H2) g2

1161
Akash Anand
·Jan 23 '13 at 3:32
Well ..what would be the answer if the cone is replaced by a right circular cylinder of same base area and same height. This is a hint for this question.
337
Sayan Sinha
·Jan 24 '13 at 8:56
Sir,
Is this height the height of the cylinder? If yes, may I know at how much depth this cylinder is kept?
Also, do we have to find out how much force is exerted on the lateral surface of the cylinder or throughout the entire surface of the cylinder?
Thanx...
1
Prashant Kulthia
·Jan 25 '13 at 8:25
Is total force=(2pi*R(∫(pi√(R2+H2)))*rho*g*∫H).....???
1161
Akash Anand
·Jan 29 '13 at 3:43
The answer will be (piR^2H-1/3 piR^2H)(rho)g
158
Anik Chatterjee
·Mar 6 '13 at 6:03
B=pVg=TTR2pgH3=pressure on curved part+pressure on base
pressure on base=pgHTTR2
Pressure on curved surface=B-pressure on base=TTR2pgH3-pgHTTR2