12) STATEMENT IS TRUE AND REASON IS ALSO CORRECT .
1)
A:potential at a point in induced elec field is not defined
R:induced electric field lines are always closed and hence work done on pt. charge by elec. field in round trip wont be zero
2)
A:work done by constant force is independent of path followed.
R:Work done by a force depends upon the component of displacement in direction of force
3)
A: in spherical body,performing pure rolling motion,point of body which is in contact with surface leaves surface perpendicularly
R:Horz acc .of point of contact is zero at the tiem of contact
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13 Answers
106(1) A (bcz second statement proves that induced electric field is non-conservative hence potential cannot be defined)
23for 2nd , it would be true only if it was a conservative force
so it shud be A is wrong , R is correct
23Q1 very true , and as asish mentioned , it aint a conservative field , hence PE cant be defined for it and hence potential cant be defined
106but qwerty the force is a constant force (in mag as well as direction)
23is ur doubt that a constant force is always a conservative force or not???i also was thinking abt it
1a constant force will be conservative won't it
here
W=\int F.dx =F.d \cos\theta
work done by the force will depend only on the end points of the motion and it will be zero is displacement will be zero.
24Does constant force mean direction and magnitude fixed ???or only magnitude fixed
24kk
in that case i think assertion is rite...
and constatn force is conservative force
plz try Q3 too
13.
A confusion btwn a&b....I would hav marked 'a'....
Both stmts r true.......
As the point of contact is the instantaneous axis of rotation, the instantaneous velocity of any point on the rolling body is perpendicular to the line joining the point of contact and the point concerned. circumference of the body, the line becomes almost horizontal as the point comes closer to the point of contact. hence its instantaneous velocity is vertical...