an electron with a speed of 1.2 .10^7 m/s moves horizontally into a
region where a constant vertical force of 4.5 . 10 -16N acts on it
mass of electron is 9.11 . 10-31 kg
find vertical distance electron is deflected durin time it has moved
30 mm horizontally ?????
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UP 0 DOWN 0 0 2
2 Answers
49this is equivalent to a projectile thrown horizontally and having vertical acceleration..:)
so..
vx= given vel of electron
dist = dx
so time taken= dx/vx
now ay=Fy/me
and dy=12ayt2
putting values it comes to approx 1/64 X 10-1=1.5625X10-3
1t = dv = 30 x 10-31.2 x 10 7 = 25 x 10 -10 sec.
a = Fme = 4.5 x 10-169.1 x 10-31 = 5 x 104 m/s2
using S = (1/2)at2 since initial velocity ' u ' in vertical direction is zero
so S = 12 x 5 x 104 m/s2 x (25 x 10 -10)2 = 1562.5 x 10-6 m = 0.1562 cm
