?????????????????????????plzzz guyssss
A solid sphere of mass m rolls down a inclined plane of height h . find the rotational kinetic energy of sphere ???
plzz m weak at this topixc so plzzz post full solution??
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8 Answers
Anirudh Kumar
·2010-02-05 05:45:59
v^{2}= \frac{2gh}{1+\frac{k^{2}}{R^{2}}}
where k= radius gyration .
it's derivation is given in Hc verma i think?
pranav
·2010-02-06 00:21:25
yaar someone solve it and show ..............i am getting
25mgh .......................... but answer is given
27mgh
in dc pandey the question is ....given
satyajeet
·2010-02-08 21:37:07
Rotational KE is given by 12Iw2..
Bt find w first...
mgh=1/2mv2+1/2Iw2
substituting I=25mr2, and v=wr, we get w=10gh7r2
Now KErot=12Iw2=12.25mr2.10gh7r2=27mgh