BASIC MECHANICS

JEE Main 2015 Questions › Mechanics questions › BASIC MECHANICS

A solid sphere of mass m rolls down a inclined plane of height h . find the rotational kinetic energy of sphere ???

plzz m weak at this topixc so plzzz post full solution??

#Physics #Mechanics

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8 Answers

1

pranav ·2010-02-05 05:08:59

plzzz someone solve it/???

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ABHI ·2010-02-05 05:11:45

rotational energy will be 1/2Iw²

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pranav ·2010-02-05 05:14:00

final aswer yaar plzz.....formula i also knew but wat s the fibnal ans?

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pranav ·2010-02-05 05:18:17

?????????????????????????plzzz guyssss

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Anirudh Kumar ·2010-02-05 05:45:59

v^{2}= \frac{2gh}{1+\frac{k^{2}}{R^{2}}}

where k= radius gyration .
it's derivation is given in Hc verma i think?

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pranav ·2010-02-06 00:21:25

yaar someone solve it and show ..............i am getting

25mgh .......................... but answer is given

27mgh

in dc pandey the question is ....given

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pranav ·2010-02-06 04:28:53

dc pandey workbook exercise in bween ones (9.6)

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satyajeet ·2010-02-08 21:37:07

Rotational KE is given by 12Iw²..
Bt find w first...

mgh=1/2mv²+1/2Iw²

substituting I=25mr², and v=wr, we get w=10gh7r²

Now KE_rot=12Iw²=12.25mr².10gh7r²=27mgh

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