BASIC MECHANICS

A solid sphere of mass m rolls down a inclined plane of height h . find the rotational kinetic energy of sphere ???

plzz m weak at this topixc so plzzz post full solution??

8 Answers

1
pranav ·

plzzz someone solve it/???

1
ABHI ·

rotational energy will be 1/2Iw2

1
pranav ·

final aswer yaar plzz.....formula i also knew but wat s the fibnal ans?

1
pranav ·

?????????????????????????plzzz guyssss

1
Anirudh Kumar ·

v^{2}= \frac{2gh}{1+\frac{k^{2}}{R^{2}}}

where k= radius gyration .
it's derivation is given in Hc verma i think?

1
pranav ·

yaar someone solve it and show ..............i am getting

25mgh .......................... but answer is given

27mgh

in dc pandey the question is ....given

1
pranav ·

dc pandey workbook exercise in bween ones (9.6)

1
satyajeet ·

Rotational KE is given by 12Iw2..
Bt find w first...

mgh=1/2mv2+1/2Iw2

substituting I=25mr2, and v=wr, we get w=10gh7r2

Now KErot=12Iw2=12.25mr2.10gh7r2=27mgh

Your Answer

Close [X]