BILLIARD BALL

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A SOLID SPHERE OF MASS M AND RADIUS R IS HIT BY A CUE AT A HEIGHT H ABOVE THE CENTRE.FOR WHAT VALUE OF H WILL THE SPHERE ROLL WITHOUT SLIPPING?

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Asish Mahapatra ·2009-05-15 23:24:22

Let the height be h.
Let the impulse be F acting for time dt
Then h*âˆ«Fdt = 2MR²/5*w (angular momentum) ... (i)
âˆ«Fdt = Mv_com (momentum) .. (ii)
v_com=wR (no slippoing) ... (iii)

solve these three u'll get h=2R/5

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BILLIARD BALL

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