bitsat 2007

the extension in a string obeying hooke s law is x .the speed of sound in stretched string is v .if extension is increased to 1.5 x then speed of sound ll be
a)1.22v
b).61v
c)1.5v
d)o.75v

10 Answers

1
prateek punj ·

is it (a).....

1
prateek punj ·

not that too sure....

1
vector ·

yaar answer provided is this only bt i ve a doubt do u solved it by taking μ(mass/length ) constant

1
prateek punj ·

i think it would decrease but i think the decrease wud be not that too large to effect the answer.....yeah the answer wud be bit greater than (a)....as i thought...

13
deepanshu001 agarwal ·

whr did u get dis actual bitsat ques frm

1
vector ·

@prateek wat i thought was that mass of d wire ll remain constant na bt as we r extending d wire by applying force n thus μ=m/1.5l
n v=√t/μ t=1.5 t initial u=μinitial/1.5
so ans mst be 1.5 v na temme wer i m wrong
@deepanshu i took it frm arihant buk

1
prateek punj ·

hmmmmmm

1
prateek punj ·

arey yaar hooke's law main F is directly propotional to extension not the length .....net length will be...L+∂L≈L

1
vector ·

oh ya tx[1]

1
prateek punj ·

wlcm....

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