33No the vertical component of velocity is not constant... at the instant after 1 sec it is 10ms-1. So after explosion also (same instant) velocity of second part should be such as that to make vcom=10 ms-1 (at that instant). So 20 ms-1
A particle of mass 2m is projected at an angle of 45 degree with the horizontal with a velocity of 20√2 m/s. After 1 sec, explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part
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5 Answers
62the vertical component initially is 20m/s
after 1 second,
it becomes 20-10.1= 10m/s
then it explodes in 2.. one comes to rest.. thus new velocity becomes 20m/s (vertical compononet again!)
So the max height from this time it can travel is 202/2.10=20m
In the 1st second it travelled 15 m..
total will be 35 m
see calculation errorrs.. :)
1but why verticle component of velocity of C.O.M will be constant
3362yup... the vertical compoent became 20 again.. (i did not mention it.. but you can see the line above
So the max height from this time it can travel is 202/2.10=20m