Circular motion

A paricle moves in the xy plane accordingly with the velocity v=(a)i+(bt)j. At the instant t=a√3/b the magnitude of the tangential, normal and the toatal acceleration are-___________,
_________ and ________.

12 Answers

·

I am telling you how to solve this problem.

You have to find the radius of curvature ( i hope you remember the formula ... if not, try to recollect [1] )
After you know R the nomal acceleration will be V2/R

Now Tangential acceleration can be simply calculated by putting value of t in dV/dt expression.

For net acceleration just take the resultant by √at2 + an2

Give it a shot ... you can solve it.

Cheers.

1
skygirl ·

have been thinking abt this for last 1/2 an hour i think............

how to find the radius of curvature [7] [7]

the curve eqn i got..

tangent we will get through that point at given time.....

but then it will be looooooooooong process.....

lokesh bhaiya mentioned abt some formula ...

any one reply // .... ant any shorter technique//

33
Abhishek Priyam ·

Radius of curvature= (1+(dy/dx)2)3/2/d2y/dx2

1
skygirl ·

haan i googled just now and found this.....

baapre......

anyways ... THANKYOU :)

33
Abhishek Priyam ·

:D

thats in NCERT maths book too...
in a question to find its value for a circle... (not specifying what it is ;)

21
tapanmast Vora ·

Priyam : I had read this sumwer is it true ?

Normal Acc = Atotalsinθ

and

Tangential Acc. = Atotalcosθ

IS THIS TRUE??? [7]

33
Abhishek Priyam ·

θ is??

33
Abhishek Priyam ·

See:

http://wiki.targetiit.com/Mechanics

I wrote tangential and normal acceleration part there.. :P

21
tapanmast Vora ·

wer θ is tan-1(∂y/∂x)

33
Abhishek Priyam ·

this is the theta not dy/dx (blue is total acc. and red are tang and normal acc...)

21
tapanmast Vora ·

priyam wo upar vala RED is tangetnial acc ne.....

THNX!!! [1]

33
Abhishek Priyam ·

Yes upar wala is tangential acc...

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