A point moves along a circle with its tangential velocity vt=0.50 m/s2 .Find the total acceleration of the point at the moment when it covered the n-th(n=0.10) fraction of the circle after the begining of the motion?
19i think something is missing......if the velocity becomes constant(as given)....then the acceleration along the tangent also becomes constant.......it should have been a time dependant velocity....please check !
1How come the unit of velocity be metre per second square? It must have been tangential acceleration?Then the resultant acceleration of the centripetal(calculate tangential velocity at the given point) and tangential acceleration would be the answer.