collision.... pls.. help...

AIEEE Coaching › Mechanics questions › collision.... pls.. help...

2 particles in air are in projectile motion having masses M₁ and M₂ and velocity v₁ and v₂ at t=t₀; collide at t=t₁ ; their velocity becomes v₁^' and v₂^' at t=2t₁,
then [(M₁v₁^' - M₂v₂^') - (M₁v₁ - M₂v₂)] is ????

#Physics #Mechanics

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8 Answers

11

jeetopper jee ·2010-10-21 06:32:00

Is the answer 2gt₁(M₁+M₂)

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11

Joydoot ghatak ·2010-10-21 08:23:51

will u pls.. explain how did u get it??

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71

Vivek @ Born this Way ·2010-10-21 08:50:25

I think it's a kind of double projectile.. HEHE

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106

Asish Mahapatra ·2010-10-21 09:34:15

as momentum during collision does not change.. so, we can simply write Î”P = FÎ”t

=> P(t = 2t1) - P(t =0) = F_ext*(2t1)
=> value required = (M1 + M2)g*2t1 (as F = external F on system = M1g + M2g)

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11

Joydoot ghatak ·2010-10-21 23:16:34

i have a very silly questn...

pls... answer this...

as during a collision, the momentum does not change..
thus, final momentum = intial momentum...

so. aint the answer be zero...

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71

Vivek @ Born this Way ·2010-10-21 23:29:03

Aren't the velocities different?

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71

Vivek @ Born this Way ·2010-10-21 23:58:52

final momentum = intial momentum... is correct.

But how are concluding yourself to 0, I don't know. Please refer to text books again as if don't seem to have right concepts.

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11

Joydoot ghatak ·2010-10-22 01:00:19

yes......... i was just washed out of my cncepts ( though i hve very little )..
i suggested the books got to know the solution to the sum.......

thanx to all...

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Your Answer

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