COM+projectile

JEE Main 2015 Online › Mechanics questions › COM+projectile

A particle of mass 2m is projected at an angle of 45 wrt horizontal wid a velocity of 20√2 m /s .After 1 s explosion takes place and the particle is pbroken into two equal pieces .As a result of this one part comes to rest.Find the maximum height achieved by the other part.

#Physics #Mechanics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

1

Arshad ~Died~ ·2009-09-04 09:57:53

apply conservation of momentum principle,,,,....find velocity.....and hence the distance

UP 0 DOWN 0
Post on FacebookPost anonymously?

6

nix_13 12 ·2009-09-04 10:04:21

will v be =40√2m/s???

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

aeroish ·2009-09-04 10:12:06

yes it will be so v = 40âˆš2m/s

UP 0 DOWN 0
Post on FacebookPost anonymously?

6

nix_13 12 ·2009-09-04 10:18:11

arre yar phans gaya hu yar.........koi solve karke batao

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω