Cool problem..laws of motion..

All surfaces are smooth and frictionless. Force constant of spring is k. What is maximum compression of spring when system is released from rest?

21 Answers

1
JOHNCENA IS BACK ·

CELESTINE
post ur solution

1
kamalendu ghosh ·

balancing forces u will get mean position,,
balancing energy u will get max compression

9
Celestine preetham ·

byah

confirm whether #3 or #4 is right

either of us mayve made a mistake

62
Lokesh Verma ·

at the end point or the lower most point when the block starts to move back to the upper direction v will be zero

hence the conservation :)

1
JOHNCENA IS BACK ·

nishant sir

plz tell how to get the above equation(in post #18)

1
JOHNCENA IS BACK ·

kx2 =2mgH (energy conserved)

i know i m asking dumb thing.......but plz tell how we get the above equation!!!!

9
Celestine preetham ·

john u r using

balancing forces technique which is wrong here
as the wedge will continue to move even afer forces are balanced (due to gained velocity)

use energy conservation

11
Gone.. ·

ya...
i considered @=45 degree

1
JOHNCENA IS BACK ·

nope RONALD

ans. is mgtan@/k

@=SLOPE OF INCLINE

11
Gone.. ·

First i got mg/√2k but then i got it........

Ans is mg/k

9
Celestine preetham ·

kx2 =2mgH (energy conserved)

H= xtanθ (constraint)

so the ans

62
Lokesh Verma ·

is theta not given?!

or do we have to solve this problem over all different values of theta..

9
Celestine preetham ·

we are taking @ as angle of inclination of wedge

1357
Manish Shankar ·

iitimcoming...

I did now understand

there are two x's!
You seem to have managed using just one!

and what is the theta you are taking?

because your answers could be the same if you and celestine and john are using the same theta

theta is not given in the question!

3
iitimcomin ·

1/2kx(m)^2 = mgx(M) x(m/M) ==> distance moved by m /M

SOLVING WE GET

x = 2mg/ktan@ ...... wonder were i went rong ?????

1
JOHNCENA IS BACK ·

mgtan@/k

@=slope of incline

3
iitimcomin ·

either of us have made a cac.

3
iitimcomin ·

yep same here cel

3
iitimcomin ·

solving it is simple ..............

only concept of constraints and engy conservation is invoved ..................... acc. to mah constraint eqxn. i got tan theta in denominater in the ans unless ive made a calc . ...................

3
iitimcomin ·

2mg/ktanθ ......................

9
Celestine preetham ·

2mgtanθ/k

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