11@iitimcomin please explain ur moi calculation
39 Answers
3i dont think so cuz there will be a reaction due to the impulse counteractin the torque produced!!!!!!!!!........if for a hoop mi is 1/2mr^2 about the cener then im pretty sure its the rite answer!!!!!!!may be an error!!!!
3i think sankara checked that MI of hoop is 1/2mr^2 ............ and the MI of the particle which gets attached to the hoop is mr^2 ...............so net I =mr^2 + 1/2 mr^2!!!!!!
3yaar im not sure wat it is but going by shankara i rote 1/2 mr^2....... otherwise itll will be mr^2 ...and ull get v/2r .................for a ring itz mr^2 for sure but i dunno wat xactly a hoop is so i went with sankara!!!!!...anyway ive ans. ur SHM ques. which u asked long time back!!!!in force method....see mech forum!!!!
1it is a simple prob..
answer IS v/3r (sorry it was a typing mistake earlier itna toh samajha karo yaaro thodi galati toh ho hi jaati hai!!)
i think no one of you have shifted the COM the MOI will be 3/2 mr2 after that
3philip ive done that and if u solve it ull get 2v/3R......see my post #19
3of course not ....... conserve ang. mom. about cener of hoop ull get mvR =(3/2mR^2)w..
w = 2v /3 r .............radius of hoop is R not R/2.......and its 3/2 mr^@ only if MI of hoop id mr^2/2...im not sure of wat a hoop is!!!!
24hoop is a ring dear.................havent u seen a basketball hoop........its same as ring...................i gave u teh link to study.......[1]
1see iitimcom.. the ang momentum has to be conserved for the system containing both so u can't do that...
and im sorry again for the typing mistake
it must have been awful to read such a thing...
3and sry for the confusion
moi for a hoop abt its diameter is 1/2mr^2
and moi abt its center of axis is mr^2
24whats happening now?????????????????it means i read it rong.........why didnt u tell me that sankara then only?????
3@philip say wat...wat cant u do?????????u can comnserve ang. mom about any point!!!!!!!! theres no torque about any point!!!!!
1[9] you scared me sankara......wen i saw that mistyped one above...
11conserving angulaar momentum
i get v/2R ( i took moi as 2mr2 itz mr2 for hoop)
3moi for a hoop is 1/2mR2
but there is an additional mass is present at a distance of R from the com
therefore I=1/2mR2+mR2
3no da i have verified it in Resnick and Halliday
actually i have some confusion abt the diff between hoop and ring
24for sankara........
http://solomon.physics.sc.edu/~tedeschi/demo/demo12.html.
24yup..........saurabh is rite........I was about to say that....[3].....i was busy with moi[2]........sankara did u see that?????