correct me

39 Answers

1
Philip Calvert ·

is R = R /2 iitimcoming ??

sry about that edited now..

11
Subash ·

@iitimcomin please explain ur moi calculation

3
iitimcomin ·

i dont think so cuz there will be a reaction due to the impulse counteractin the torque produced!!!!!!!!!........if for a hoop mi is 1/2mr^2 about the cener then im pretty sure its the rite answer!!!!!!!may be an error!!!!

11
Subash ·

for a hoop moi is mr2

3
iitimcomin ·

i think sankara checked that MI of hoop is 1/2mr^2 ............ and the MI of the particle which gets attached to the hoop is mr^2 ...............so net I =mr^2 + 1/2 mr^2!!!!!!

24
eureka123 ·

@iit....see my post#9 and follow the link...........[1]

3
iitimcomin ·

yaar im not sure wat it is but going by shankara i rote 1/2 mr^2....... otherwise itll will be mr^2 ...and ull get v/2r .................for a ring itz mr^2 for sure but i dunno wat xactly a hoop is so i went with sankara!!!!!...anyway ive ans. ur SHM ques. which u asked long time back!!!!in force method....see mech forum!!!!

1
Philip Calvert ·

it is a simple prob..

answer IS v/3r (sorry it was a typing mistake earlier itna toh samajha karo yaaro thodi galati toh ho hi jaati hai!!)
i think no one of you have shifted the COM the MOI will be 3/2 mr2 after that

24
eureka123 ·

ok i will check that.........[1]

3
iitimcomin ·

philip ive done that and if u solve it ull get 2v/3R......see my post #19

24
eureka123 ·

and ans is v/3r

3
iitimcomin ·

of course not ....... conserve ang. mom. about cener of hoop ull get mvR =(3/2mR^2)w..
w = 2v /3 r .............radius of hoop is R not R/2.......and its 3/2 mr^@ only if MI of hoop id mr^2/2...im not sure of wat a hoop is!!!!

24
eureka123 ·

hoop is a ring dear.................havent u seen a basketball hoop........its same as ring...................i gave u teh link to study.......[1]

1
Philip Calvert ·

see iitimcom.. the ang momentum has to be conserved for the system containing both so u can't do that...

and im sorry again for the typing mistake
it must have been awful to read such a thing...

3
msp ·

and sry for the confusion

moi for a hoop abt its diameter is 1/2mr^2

and moi abt its center of axis is mr^2

24
eureka123 ·

whats happening now?????????????????it means i read it rong.........why didnt u tell me that sankara then only?????

3
msp ·

oh sry eureka mistyped the above thing

3
iitimcomin ·

@philip say wat...wat cant u do?????????u can comnserve ang. mom about any point!!!!!!!! theres no torque about any point!!!!!

3
msp ·

no soln philip waiting for the momentum institues soln da

1
Philip Calvert ·

[9] you scared me sankara......wen i saw that mistyped one above...

11
Subash ·

conserving angulaar momentum

i get v/2R ( i took moi as 2mr2 itz mr2 for hoop)

3
msp ·

moi for a hoop is 1/2mR2

but there is an additional mass is present at a distance of R from the com

therefore I=1/2mR2+mR2

24
eureka123 ·

hoop is a ring naa???????????moi for ring=mr2

3
msp ·

no da i have verified it in Resnick and Halliday

actually i have some confusion abt the diff between hoop and ring

24
eureka123 ·

[12]

1
Saurabh ·

how can u conserve energy the collision is perfectly inelastic?

3
msp ·

yes saurabh u r rite

if u got any ans please post da

24
eureka123 ·

for sankara........
http://solomon.physics.sc.edu/~tedeschi/demo/demo12.html.

1
Saurabh ·

SO THE NEXT OPTION WE HAVE IS CONSERVING MOMENTUMS

24
eureka123 ·

yup..........saurabh is rite........I was about to say that....[3].....i was busy with moi[2]........sankara did u see that?????

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