correct me

how this....(I=1/2mR²+mR²)........i may be sleepy so plz forgive me if my doubt is rong....[2]

oops sorry eureka i made a mistake in moi

ur rite

seen the link given by u da

@subash u r rong with ur ans becos the ans is v/3R

and u have conserved angular momentum in which axis

pls explain

hey...why aren't we considering translational motion of hoop??????????Is it fixed???????[12]
I dont think so!!!![1]
try it sankara....

sankara ...just apply the conservation of angular momentum !!

GUYS !..and the picture is upside down !! (if u want the answer as v/3r)

otherwise we cant apply conservation of angular momentum !!

have u got the ans sankara or not???

but this is not given in question!!!!!!!!!
The question states that a circular uniform hoop rests on horz surface....

so how can we consider that????[12]

@ unique........ the picture is perfectly correct!!!!!!! u can conserve ang. momentum about any point .... since there is no external torques abt any point!!!!!!!
NOTE THE WORDS SMOOTH HORIZONTAL PLANE!!!!!!!!! SO UPSIDE DOWN OR NOT ITS THE SAME NOTE SYMMETRY!!!!!.......DUNNO WAT MADE U SAY THAT!!!!

so CONSERVIN ABOUT CENTER mvR = (mR^2 + 1/2mR^2)ω .........

ω = 2V/3R..................

why dear???????????there is torqu about centroidal axis due to impulse at pt of contact.....[7]