determine the speed.

A particle is moving with a velocity \overrightarrow{\mathbf{v}_0} when starting at t=0, a constant force starts to act on it. As a result, at t=t0, its speed becomes \dfrac{v_0}{2}, and at t=2t0, its speed becomes \dfrac{v_0}{4}. Determine the speed at t=3t0.

8 Answers

66
kaymant ·

that answer is incorrect rohan

1
Rohan Ghosh ·

ooopse seems a calc mistake
√(7/16) v0

66
kaymant ·

yes thats correct

1
ANKIT MAHATO ·

v/9 .. pure guess :)

1
Dharun ·

rohan plz post the soln

66
kaymant ·

ankit look at rohan's answer

1
noone ·

t0 = v0/2 ;;; acc for first time interval = -v0/2t

t1= 2t0 = v0/4 ;;; acc for second time interval = -v0/4t

....

acc for third time interval = -v0/8t

so,

v02/16 - v2 = 2 (-v0/8t)[v0t/4 - 1/2.(-v0/8t )t2]

=> v2 = √7v0/64

oho... where am i wrong [12]

1
rajat sen ·

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