1but the normal force acts along the center of mass only..........so torque should be zero.
Then why it has some value?????
although ur answer is correct.
Question. A block having equilateral triangular cross-section of side a and mass m is placed on a rough inclined surface,so tat it remains in equilibrium . The torque of normal force acting on the block about its center of mass is ?????
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49the torque due to normal force in the anticlockwise direction will be equal to the clockwise torque due to friction....
friction acting=downward force along the incline plane =mgsinθ
the dist of base of eq. Λ from centre of mass=a/2√3
thus torque due to normal reaction=mgasinθ/2√3..........hope this matches the answer.....
well it must...
149yeah there is just the question i was hoping......i had a similar misconception......bt the reason is here as it goes........
suppose u r standing and a friend is constantly pushing u....if u stand straight u will surely fall.....but to avoid that u spread your legs and in doing so u shift your normal reaction so as to balance the torques........
similar is the case for blocks......when there is a tangential force acting on a non circular body, it tries not to roll and so quite amazingly and magically shifts the normal reaction so as to balance the torques..............oterwise imagine a rolling block.........[1][1][1][1][3][3][4][4][4]