DOUBT

i) A
ii) B
r dese correct?

plzz post ur full solution.........i dont noe the answers

it was asked by nishant sir,,,

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wht to write there

i) Consider the vertical motions of each ball. The ball B starts with a zero initial vertical velocity and falls with a constant acceleration g. The ball A also starts with a vertical zero velocity but as it goes down, the acceleration in the vertical direction decreases continuously starting from g. Since both fall by the same vertical distance, the time taken by A has to be greater.

(ii) The distance covered by A is obviously \pi/2 m.
On the other hand the horizontal distance covered by B is given by
\sqrt{2g}\sqrt{\dfrac{2}{g}}=2 m
So the straight line joining the initial and final position of B has a length \sqrt{5} m which is already greater than \pi/2 m. And the arc length of the path of B is greater than \sqrt{5} m.

So B covers greater distance in a shorter time.