doubt!!

The only criteria is that since no external force acts on the 10M and M system, the x coordinate of the centre of mass should be fixed

So, if 10M moves x1 to right and M moves x2 to left then 10M.x1 + M.x2 = 0

=> x2 = -10x1 ... (I)

also the total relative length moved by the system is 2.2m

So, x1+ x2 = 2.2 ... (II)

Solve these two and get answer

rite way is given by asish..

but if u can remeber a formula..
x=mhcotθ/m+M

then also its OK [1](atlest for this ques)

ok..here is derivation of that formula..

Since net force on wedge +block system=0 in horz direction..so CM doesnt displace in horz direction

So,
x.M=x_r.m

here x_r is relative diplacement of block wrt ground...(in op direction to wedge ofcourse)
and x=dipslaceemnt of wedge

=> x.M=(-(x-hcotθ)).m
=> x.M=(hcotθ-x)m

Solve for x now [1]