1the derivative of the function can never be zero.so what i think is can never attain any kind of equilibrium.
IF ENERGY OF A PARTICLE IS 'U' AT THE ORIGIN ..AND the object's movement is restricted along the X axis only ..such that U= Log |1+e2x| J
DERIVE THE CONDITION FOR FOLLOWING TYPES OF EQUILIBRIUM :
1) stable
2) unstable
3) neutral
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UP 0 DOWN 0 0 4
4 Answers
1
1but.... can u plz tell ..how to derive any kind of equilibrium ? ?
do we differentiate eqn wrt x axis and equate it to zero ..plz help ..just tell the method..for obtaining different types of equilibrium
1yup...
At eqb F=0 => dU/dx = 0
Now if d2Udx2 > 0 (or equivalently dFdx<0 ),ie, U is min then Stable Eqb
if d2Udx2 < 0 (or equivalently dFdx > 0) ,ie, U is max then Unstable Eqb
if d2Udx2 = 0 (or equivalently dFdx = 0) then Neutral Eqb