energy

IIT JEE 2015 Forum › Mechanics questions › energy

. A particle, which is constrained to move along the x-axis, is subjected to a force in the same direction which varies with the distance x of the particle from the origin as F(x)= - kx + ax3 . Here k and a are positive constants. For x â‰¥ 0 the functional value of the potential energy U(x) of the particle is

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2 Answers

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Debanjana Mukher ·2009-12-27 03:14:38

is it (d)??

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varun.tinkle ·2009-12-27 04:14:21

here u=kx^2/2-ax^4/4 hope u can solve it after that

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Basic Integral Calculus Operators Symbols Matrix Cases

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω