1koi toh batao yaar....
CONCEPT :- For a system to be in equilibrium, the torques acting on it must balance. This is true when we take torques about any point on the system or outside it.
DOUBT :- Does the above statement hold when the system is in only rotational equilibrium but has translational motion???? PLZ EXPLAIN
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11 Answers
71"For an object to be in static equilibrium, not only must the sum of the forces be zero, but also the sum of the torques (moments) about any point. For a two-dimensional situation with horizontal and vertical forces, the sum of the forces requirement is two equations: ΣH = 0 and ΣV = 0, and the torque a third equation: Στ = 0. That is, to solve statically determinate equilibrium problems in two-dimensions, we use three equations."
Thus, I think that above statement is valid/True only for Rotational Equilibrium and not for Translational motion.
11CONCEPT :- For a system to be in equilibrium, the torques acting on it must balance. This is true when we take torques about any point on the system or outside it.
DOUBT :- Does the above statement hold when the system is in only rotational equilibrium but has translational motion???? PLZ EXPLAIN
This is valid only for the body to be in rotational equilibrium.
11For the body to be in rotational as well as translational equilibrium,
1) the vector sum of all the forces that act on it must be ZERO
2)Th vector sum of all the external torques that act on body, measured about any possible point MUST BE ZERO.
Further if the body has to be in static equilibrium then there is one more condition
3)the linear momentum P of the body must be zero.
1@ khyati.... plz try solving 1st qstn of 'DYNAMICS OF SOLID BODY' from IE IRODOV taking torques abt point of application of F1 ...
11Arey Euclid, Irodov ko hath tak nahi lagaya hai abhi tak maine. Let me first learn to solve the
question of HCV completely.
I am very sorry I can't help you.:(
Ask Subhomoy for help
1arey its alright...infact i hav got my answer....thnx for ur coordination :)