see i will solve the whole sum.... assuming u know constraint eq ....
first according to constraint .... eq..... simply acc f mass 2 is two times that of mass 1 .... so
nmg-t=2nma
and 2t-mg=nma
solving it we get a
=mg(2n-gsin@)/4n+1
but since acc of mass m2 is twice so acc becomes 2a
5 Answers
Here again swastika..
let5 us try and follow the same principles taht i told in the previous post...
1) The relationship between different tensions in the strings
2) The direction of tension (A lot of students mess up the direction of tension)
3) The relation ship between the acceleration of the different bodies involved. (This is teh most crucial step for all such problems)
4) The FBD
5) The Force Equations from newton's law
6) Solving these equations....
let tension is string near 1st mass be T1 and near mass 2 be T2..
Let accel. of mass 1 be w1.
T1=2T2 ---------(1)
therefore,w=2w1 ----------(2)
T1-m1gsin @ =m1w1 --------(3)
m2g-T2 = m2w --------(4)
pls solve 1,2,3,4 to get ur w..if it doesnt come tell..there cud be some silly mistake in the 4 equations.
but generally if it was movable.. the mass would have been specified.. or those hatched lines would not be drawn