since there is no relative motion only forces acting are
on m==>
1.Normal reaction(N1) upwards
2.weight=mg downwards
on M===>
1.N1 downwards
2.normal reation due to ground(N2)
3.weight =Mg downwards
Find the forces on the block blocks (including friction) The friction between the lower and upper block is N and lower and ground is n
since there is no relative motion only forces acting are
on m==>
1.Normal reaction(N1) upwards
2.weight=mg downwards
on M===>
1.N1 downwards
2.normal reation due to ground(N2)
3.weight =Mg downwards
@#5
on m==>
1.Normal reaction(N1) upwards
2.weight=mg downwards
3.friction=N in forward direction
on M===>
1.N1 downwards
2.normal reation due to ground(N2)
3.weight =Mg downwards
4.friction N in backward direction
5.friction n in backward direction
On block M:
Mg downwards
N1 upwards = (M+m)g
n towards left
N towards right
On block m:
mg downwards
N2 upwards = mg
N towards left
but actual force depends on magnitude of N and n...
Perfect Answer Asish
You have to mention that
N<n for your result