A spherical small ball of density p is gently released in a liquid of density ∂ (p > ∂ ) . The initial acceleration of the free fall of the ball will be :
a) p + ∂p g
b)p - ∂∂ g
c)p - ∂p g
d)g
the answer given is c
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1 Answers
49let volume be V
weight downwards=pVg
upthrust upwards=∂Vg
net force downwards=(p-∂)Vg
acceleration downwards=forcemass=(p-∂)Vg∂V=p-∂p.g
hence C
