49
Subhomoy Bakshi
·2009-12-26 09:28:33
difference in pressure on either side of fluid...
33
Abhishek Priyam
·2009-12-26 09:30:15
its 4 others to try or ur doubt? if u want xplanantion i can give it or else leave it 4 others
33
Abhishek Priyam
·2009-12-26 09:50:27
What I feel is
so pv=nRT neither T nor n changes so only thing that can happen is v increases..
This happens in two ways..
first if the cardboard is little flexible it slightly bulges in the center thus increasing volume
and also card comes a little below (looses contact with glass ) and remain sttuck due to surface tension with glass (water in between glass and card)
Both together adds to increase in volume.
You can try slide the card it slides smoothly(and water falls ofcourse ;) because of water in b/w
1
Amritansh Bharech
·2009-12-26 09:50:50
the pressure inside is due to the liquid and the gas which is less than the atmospheric pressure acting outside
33
Abhishek Priyam
·2009-12-26 09:58:39
actaully i missed the 3rd point..
a little of water escapes while tilting thus increasing volume for air..
33
Abhishek Priyam
·2009-12-26 10:00:52
@qwerty the weight of liq is same..
waht we are ending in is a long lost post abt P + h2 g = P1 and weight of water
33
Abhishek Priyam
·2009-12-26 10:14:56
i can't figure out ur eqns.. what are P1 and P and wht are hts..
49
Subhomoy Bakshi
·2010-03-13 12:23:22
look i now have a separate viewpoint on this....
in the glass we all know air pressure is same on either end...
now,
in the downward side, ie the cardboard, the upward force acting=PAXarea of cardboard..
on upward side, downward force=PAXarea of fluid..
thus net upward force=PAX(area of cardboard-area of fluid surface)
now we can see that area of card board must be higher that the upper liquid surface for the cardboard to cover the tumbler completely..
and PA is a huge amount so the net upward force is HUGE.. which balances the downward weight!!
that is my viewpoint...awaiting replies!!