the solution seems fine, but I have one query. After the ball has entered water, its force downwards = mg , but doesn't force upwards include viscous force( 6Ï€(eta)rv )) and buoyant force, how can u assume that it will attain terminal velocity immediately after falling in???
[7][7][7]
a ball whose density is 0.4 * 103kg/m3 falls into water frm a height 9 cm.to wat depth i will sink???
1.9 cm
2.6 cm
3.4.5cm
4.2.25cm
-
UP 0 DOWN 0 0 3
3 Answers
virang1 Jhaveri
·2009-04-09 04:16:39
d/M* gD
M*g/0.4
is the upward force
Downwards force = MG
Resultant force = 6MG/4 = 3MG/2
MGH = Mv2/2
g * 9*10-2*2 = v2
V2 = 2as
S = g * 9 *10-2*2*2 /2*3g
S = 3*210-2
S = 610-2
S = 6cm
Option 2.
cipher1729
·2009-04-09 04:27:12
virang1 Jhaveri
·2009-04-09 06:19:49
Here i have not considered viscocity.
But if n(eta) and r is given then we have to consider viscous force