11Volume =Area * Height
V =AH
Upthrust = VDG
Upthrust = AHÏG
a triangular lamina of area A n height H is immeresd in a liquid of density Ï in a vertical plane with its base on the surface of the liquid.the thrust on the lamina is??
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4 Answers
1volume of cone is:
1/3 πr2h == 1/3 X A X h
so upthrust should be :
1/3 X A X h X Ï Xg
3if u want the net force on the lamina ................................
let us divide into rods ..................................
now assuming the top of the lamina is just on the surface ...................
A = 1/2 Hb ............
A/H = b/2 .........[b=base length].....
A/H2x = y ............[as we divide into segments dx in thickness and x is mesured top]
[ y = 1/2 length of the rod at that x ]
pressure at depth x = Pgx [P =density]
Pgx2(dx)(2A/H2) = dF ///////
(2/3)PgAH = F ........................
[i think by thrust u want the net force on the lamina viashnavi .....]
3sorry ive done the above with the top part on the surface [didnt read ur question carefully[2]]...............
i think u can do it for base on the surface using my above approach......
