Force and Friction


A block of mas m rests on a bracket of mass M. The coeff of friction b/w the block and bracket are @s and @k. The bracket rests on a frictionless surface. Show that the max force F that can be applied if the block is not to slide on the bracket is given by
[@s mg (M+m)] / (M+2m).

3 Answers

1357
Manish Shankar ·

From the FBD we have

2F-f=Ma (1)
f-F=ma (2)
f=μsmg (3)

solve the above three to get answer

1
sanchit ·

But still the ans is not coming , sir

1357
Manish Shankar ·

2F-f=Ma (1)
f-F=ma (2)
f=μsmg (3)

dividing (1) be (2) we get

(2F-f)/(f-F)=M/m

or 2mF-mf=Mf-MF
or (2m+M)F=(m+M)f

(2m+M)F=(m+M)μsmg

or F=(m+M)μsmg(2m+M)

:)

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