force

JEE Main 2015 Online › Mechanics questions › force

force F_vector=yi +xj acts upon a particle of mass m
here how we can check that whether origin is unstable or stable equilibrium

#Physics #Mechanics

UP 0 DOWN 0 0 5
Post on FacebookPost anonymously?

5 Answers

Ghosty ·2009-03-26 04:52:36

U=-âˆ«(yi+xj)(dxi+dyj)
Î”U=-xy

i think unstable equilibrium...

UP 0 DOWN 0
Post on FacebookPost anonymously?

ANKIT MAHATO ·2009-03-26 05:29:08

-dU/dx = yi ... U = -xy
-dU/dy = xj ... U = -xy

therefore U = -xy

at origin it is 0 ... at some other point it can be positive or -ve .. therefore at origin it niether attains maxima or minima .. so it is in unstable eq .

UP 0 DOWN 0
Post on FacebookPost anonymously?

Abhishek Priyam ·2009-03-26 05:54:23

Both are correct..

it is unstable equilibrium...

UP 0 DOWN 0
Post on FacebookPost anonymously?

deepanshu001 agarwal ·2009-03-26 06:42:32

can sum1 elaborate ghosty s technique

UP 0 DOWN 0
Post on FacebookPost anonymously?

Abhishek Priyam ·2009-03-26 07:01:27

It is easy.. just multiply.... them and you will get ydx+xdy=d(xy)

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

force

5 Answers

Your Answer

Add Image

Similar Questions