1anyone ??
The coefficient of friction between an insect and a hemispherical bowl of radius r is \mu. The maximum height to which the insect can crawl in the bowl is
A) \frac{r}{\sqrt{1+\mu ^{2}}}
B) r\left[1-\frac{1}{\sqrt{1+\mu ^{2}}} \right]
C) r\sqrt{1+\mu ^{2}}
D) r\left[ \sqrt{1+\mu ^{2}}-1\right]
ans -----------> (B)
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2 Answers
1Let angle subtended at the centre of bowl in limiting case=θ
mgcosθ=μmgsinθ
μ=tanθ .This implies cosθ=1√μ2+1
Let h be the height which is given by h=R-x
where x=Rcosθ
h=R-Rcosθ
h=R(1-cosθ)
h=R(1-1√μ2+1)