I dont know what is eqn 17.13..........
but I am replying to rest of the parts.....
vo= 0
f'=[v/v-vscosθ]f
But cosθ=4/5
so, f'=[343/343-0.8(25)]500 =531 HZ
Since 0<θ<180
so, f']max=[v/v-vscos0]f =539HZ
& f'min=[v/v-vscos180]f=466HZ
I dont know what is eqn 17.13..........
but I am replying to rest of the parts.....
vo= 0
f'=[v/v-vscosθ]f
But cosθ=4/5
so, f'=[343/343-0.8(25)]500 =531 HZ
Since 0<θ<180
so, f']max=[v/v-vscos0]f =539HZ
& f'min=[v/v-vscos180]f=466HZ
Since source and observer moving away from each other
so,θo-θs=180........Is this hint enough.????