n=2 only
Consider an attractive central force of the form F(r) = -k/rn where k is a constant. For a stable circular orbit to exist what should be the value/values of n?
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11 Answers
i think if i m right then n≥1 as for stable orbit -∂F/∂r is negative as potential energy is minimum thinking so ..
sorry and thanx aragorn for giving those comment i had use wrong relation its answer will be n≥2 as ∂U/∂r =-F and for stable equilibrium P.E. must be negative then intgrate it then u will get if n≥2 then we will get -ve P.E. i had not use vector notatiuonof formula ok
F(r) = -k/rn
What is the significance of the negative sign? Can't we combine it with k and write it as another K?
this is a nice question... i think rahul is nearest to the explanation...
we need to kp in mind dat 'stable' thing...
but there's something more lucid...
well still thinking ....