1thanks subhomony........
can any one solve the 2nd Q also.......the Q is actually solved using elliptic orbits........
Q The objects lying at the equator will fly off the surface of the earth. if the speed of rotation of the earth increases n times its present value then n is _______
Q The largest and the shortest distance of the earth from the sun are r1 and r2, its distance from the sun when it is at perpendicular to the major axis of the orbit drawn from the sun is
answer: 2 (r1r2)/r1+r2
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2 Answers
491) GMmR2 - mω2R = mg
and, GMmR2 = m(n2)ω2R
GMmR2 = n2. [GMmR2 - mg]
that will give us n in terms of known G M and R!! :)
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