1oh am sorry.....
two particles are projected simultaneously in the same vertical plane, from the same point, but with different speeds and at different angles to the horizontal.
find the path follwed by one, as seen by the other.... ??
a) a vertical strait line.
b) a str line constant slope.
c)a parabola
d) a hyperbola.
e) an unkown trajectorywhich cudnt be defined :P
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20 Answers
1arey waisa option hai kya question me ?
there can be 100 other diff cases..
abhi exam hai 9am se ... shaam ko ake saaaaaaaare cases discuss karenge .. thik hai naa [3]
1@ the scorpion
"well, ur options are funny... second one... a str line constant slope... obviously a straight line will have a constant slope rite... "
.. dude and sky i want to say just one thing .. what if the relative velocity in the x direction had been 0 .. then the path followed by one, as seen by the other had been vertically upwards ... in this case the angle the line made by the line and the x-axis had been 90° and the slope of the line in that case had been not defined (which is not a constant) .. so the answer had been only a straight line .. nothing else specific ...
1my frnd (lazyness) will get disappointed if i do dat... [3]
well, dats cool... [1]
1it is done in the very first post itself....
read the whole thread dear...
1well, ur options are funny... second one... a str line constant slope... obviously a straight line will have a constant slope rite... [3]
well, is this sum done... or still d final answer is yet to come...!!??? [12]
is d answer given by ragadeepika correct...???
106(b) this is because..
v2 - v1 = (u2cosθ2-u1cosθ1)i + (u2sinθ2 - u1sinθ1)j which is a constant vector.... So, in general ans is (b) in special cases it can be (a) can u calculate when will ans be (a) sky??
1Well..you haven't noticed my reply carefully...
Its true that the displacement and velocities are vectors, of course.
But, I have divided them into two scalar equations for each particle.
That is as per the two axes.
In such cases, they are the components of a vector, which I've taken into consideration.
1well one thing... all the quantitties in ur equations has to be vectors...
1yep .. u are right only...
put the values and chcek urself once...
waise not a big deal.... its an easy one :)
1We can clearly see from the question that we need to find relative velocities of the particles.
Let the initial velocity of the particles be u1 and u2 respectively.
The displacement at any instant t can be given as follows -->
S1(x) = u1(x)t
S2(x) = u2(x)t
S1(y) = u1(y)t - 1/2gt2
S2(y) = u2(y)t - 1/2gt2
The relative velocities along the two directions is
Srel(x) = ( u1(x) + u2(x))t
Srel(y) = ( u1(y) + u2(y))t
From the above two equations, we can see that they are linear equations. In other words, the path of one particle as seen by the other is a straight line.
I hope this helps you
ALL THE BEST
106okkk y cant it be when u1sinθ1 = u2sinθ2 then it will be a horizontal straight line.....
1this isnt my doubt ashish...
(wenevr i gv a title like gud1 or solve it .. .then its meant for others only :) waise, gud dat u did it :) and yeah if u1cosθ1=u2cosθ2, then its vertical line :))