i want the method

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from a circular disc of radius R & mass 9m a small disc of radius R/3 is removed whose centre is at 2R/3 . find the moment of inertia of remainning disc about an axis perpendicular to the plane of disc & passing through centre of disc.

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greatvishal swami ·2009-01-08 00:43:36

sm1 pls giv the method fr it 2

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Philip Calvert ·2009-01-08 04:39:38

calculate the moment of inertia of the small disc about the centre
this should be easy mass can be calculated since disc has to taken of uniform density
subtract the moment of inertia from that of the bigger disc 9/2mR²
simple [1]

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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i want the method

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