3hey this is not in jee syllabus!!!!!
An artificial satellite is in circular orbit around the earth. The universal gravitational constant starts increasing at time t = 0, at a constant rate with respect to time. Then the satellite has its
1. path gradually spiralling in towards the centre of the earth.
2. path gradually spiralling out away from the centre of the earth.
3. angular momentum about the centre of the earth remains constant.
4. potential energy decreases.
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16 Answers
3Pressure in a fluid; Pascal's law; Buoyancy; Surface energy and surface tension, capillary rise; Viscosity (Poiseuille's equation excluded), Stoke's law; Terminal velocity, Streamline flow, Equation of continuity, Bernoulli's theorem and its applications.
3it starts spiralling inward!!!!!!!
potential energy goes on decreasing!!!!!!!!
"""""angular momentum about the centre of the earth remains constant.""""""" ang. momentum of wat about the center of the earth?????? if its the ang. momentum of the earth aby center of the earth then it remains constant = 0!!!!
3and shubhash check out the SHM and also the question of the day id u like physics a lot!!!!
3if its the ang. mom. of satlite .. it is not constant as the thing keeps spirallin inward .......
11no it is conserved consider the gravitational force
it is a central force
if it is spiralling inwards its velocity is increasing(radius is decreasing)
3the central force is perpendicular to the tangential velocity so it plays no role ... tangential velocity is a constant !!!!!!
106sankara 2 can never be the answer..... as G increases , then attractive force will increase, so it will spiral inwards.
3F=GMm/R2 (G=kt+G0)
1/2mv2-G0Mm/(R+h)1=1/2mv'2-(kt+G0)Mm/(R+h+h')1
V(R+h)=V'(R+h+h') (since ang.mom is conserved bcos rFsin0=0)
substitute for V' and find h'.
v'=√g(R+h+h')