IIT JEE past question Mechanics 2

VITEEE Guidance › Mechanics questions › IIT JEE past question Mechanics 2

a syringe of diameter D=8mm and having a nozzle of diameter d=2 mm is placed horizontally at a height of 1.25m as shown in the figure.
An incompressible and non viscous liquid is filled in syringe and the piston is moved at speed of 0.25 m/s .

Find the range of liquid jet on the ground.

#Physics #Mechanics

UP 0 DOWN 0 0 6
Post on FacebookPost anonymously?

6 Answers

Â°áƒ¦â€¢à¹“ÑÏ…Î ·2009-03-30 07:29:42

is d figure invisible :P :O

UP 0 DOWN 0
Post on FacebookPost anonymously?

virang1 Jhaveri ·2009-03-30 07:30:10

Sir cannot see the figure

UP 0 DOWN 0
Post on FacebookPost anonymously?

iitimcomin ·2009-03-30 07:31:40

AV = av

V = av/A

0.25 A/a = v

0.25(16) = v edited 64->16 [calc error]

4 = v 1

4âˆš2(1.25)/g = 4âˆš0.25 = 2

UP 0 DOWN 0
Post on FacebookPost anonymously?

Lokesh Verma ·2009-03-30 07:31:49

coming up :D :P

UP 0 DOWN 0
Post on FacebookPost anonymously?

virang1 Jhaveri ·2009-03-30 07:35:48

AV =av
4*4*0.25 = 1 * v
v = 4m/s
S = gt²/2
1.25*2 = 10t²
2.5 = 10t²
25/100 = t²
t = 5/10
t = 0.5 secs

x = 4 * 0.5

Range = 2m

UP 0 DOWN 0
Post on FacebookPost anonymously?

iitimcomin ·2009-03-30 07:39:00

sorry my calc. mistake ...............took 4*4 = 64 .....[3]

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

IIT JEE past question Mechanics 2

6 Answers

Your Answer

Add Image

Similar Questions