Sir I'm also getting 3ml2 but in FIITJEE solution they have used ml2. I don't understand how .
ml2/3 + (ml2/3 + ml2) + (ml2/3 + ml2) = 3ml2
Am I right Sir ??
Anyways.....is then Fiitjee's soln. wrong ?
Till now unlucky 13 views and no reply....I hope someone is racking his/her brain through it !!! :-)
It should be 3mL2 if the mass of each rod is m and not mL2 as you have written.
Sir I'm also getting 3ml2 but in FIITJEE solution they have used ml2. I don't understand how .
ml2/3 + (ml2/3 + ml2) + (ml2/3 + ml2) = 3ml2
Am I right Sir ??
Anyways.....is then Fiitjee's soln. wrong ?
Obviously the FIITJEE solution is wrong. And that's not a new thing. (They might have m as the total mass though.)