using bernoulli's eqn,
Ïgy = 1/2*Ï*vhole2 (since radius of hole is very small)
vhole = √2gy
using eqn. of continuity ,
Asurfacevsurface = Aholevhole
applying corresponding values ,
vsurface = r2√2gyx2 = c (constant)
thus y = k * x4
The shape of a water clock jar is such that water level. Descends at constant rate at all times.is it falls by x m/s,shape of jar is given by y proportional to x^n find value of n if radius of drain hole is r and can be assumed to be very small
Answer=4
Please explain how you solved it!
using bernoulli's eqn,
Ïgy = 1/2*Ï*vhole2 (since radius of hole is very small)
vhole = √2gy
using eqn. of continuity ,
Asurfacevsurface = Aholevhole
applying corresponding values ,
vsurface = r2√2gyx2 = c (constant)
thus y = k * x4
Hmm, Thanks. This turned out to be easier than I thought.