1ya it should be 8√3.
a particle is released from the top of an equilateral triangle groove which is meeting in th plane of an inclined plane of inclination theta= 53°. the corner of the groove are curved to neglect impulse. side of a triangle is 8√3 m. calculate the time of a complete round trip9at corners there is no change in speed).
ps=one mistake. the heading should have been kinematics...:P
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UP 0 DOWN 0 0 3
3 Answers
1mark the triangle as ABC with the topmost point as A.
for the motion AB,
resolve gsinθ along the goove as it is constrained to move only along the groove.
=> u = 0 ; a = gsinθ*cos30° ; s = 8√3
=> s = 1/2*at2
=> t = 2s
similarly t for the motion CA = 2s
now, for BC
using the above conditions find final velocity after A motion which comes out to be 8√3..so time taken = 8√38√3 = 1 s
.:. total time = 5s