11Apply momentum conservation
let the speed of man be v
mu=Mv
v=mu/M
the time taken by the ball to reach the floor =h/u
So position of man above floor=h+mu/M(h/u)
=h(1+m/M)
option A
in a gravity free space a man of mass M standing at a height h above the floor throws a ball of mass m straight down witb a speed u. when the ball reaches the floor , the distance of the man above the floor will be-
a)h(1+m/M0
B)H(2-M/m)
C)2H
D)HM/2m
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7 Answers
11
11in a gravity free space a man of mass M standing at a height h above the floor throws a ball of mass m straight down witb a speed u. when the ball reaches the floor , the distance of the man above the floor will be-
ISKA MATLAB BALL KO KOI FORCE NICCHE KHICCHNE WAALI NAHIN HOGI
SO I THINK THE BALL WILL NEVER COME BACK
SO UR THIS STATEMENT
when the ball reaches the floor
SEEMS INVALID TO ME
DO CLEAR MY DOUBT
AND CORRECT ME IN CASE OF WRONG THINKING
1dude but man has applied a force and set the ball in motion to reach the floor, which inturn applies a force on man
