for part 1 use binomial expansion d = √( λD)/2, for part 2 i am getting x as ( 2λD- 2d^2 ) / 2D , tell if i am correct , i'll post my attempt
2 Answers
redion
·2010-11-07 03:46:21
for part 1 use binomial expansion d = √( λD)/2, for part 2 i am getting x as ( 2λD- 2d^2 ) / 2D , tell if i am correct , i'll post my attempt