24Is it tuff ??
As far as I know ...
We need just 2 eqn
Tcosθ=mg ----(1)
Tsinθ=mω2r ----(2)
U should get the answer from here..
I hope I am not making a fool out of myself :P
12 Answers
24
3well i have a pbm in writing the force equation.in this case it is a chain na.So how we shud write the force equation.Can u explain wat u have done.
24i wrote the force eqn at that pont where thread is joined to chain
3then u have left a force,that is the force between the chain and also the mass is dm which tends to zero.
so how can u divide those eqns.
24hmm....let Nishant sir or anant sir then handle it ....
Ofcourse irodov questions are weird..[3]
66Let the distance of the center-of-mass from the axis be Ï. Write down the equations for the center of mass:
Along the vertical: T cos θ = mg
Along the horizontal: T sin θ = m ω2 Ï
Dividing
ω2Ïg = tan θ ==> Ï = g tan θω2
This is precisely what eureka wrote. However, the point is that the equations pertain to the center of mass and not the point where the thread is joined to the chain.
3thanq sir.At first i also done the same wat eure but my logic is rong.Dats y i posted here.Thanx for helping.
3sir i have a dbt the angle at which the tension acts on the com is different than theta,so the eqns were written for com is rong.pls correct me.
24i beleive what isaid in my st post was OK...
we take mass dm of that part of chain to which thread is attached..and then write the smae eqn..after all we just need to find r and T
66@msp, on the center of mass the external forces act exactly along their original directions.